Understanding Idaho Lottery Statistics

By Ross Mcbride
Today's topic of understanding the chances of winning the lottery.

Let's take an average of 6 / 49 Idaho lottery that operates in several U.S. states and Canadian provinces as an average lottery for our example. To win the Idaho lottery grand "you" as a contestant must choose all six numbers in exactly as drawn in the weekly and monthly contests.

To understand how to calculate the chances to win the lottery one simply assess the process of calculating the pool of potential numbers that you, as a contestant has a choice.

To get the first issue you have one in 49 chance of choosing the correct numbers.

To select the second issue you have a smaller pool of potential numbers available for your choice. To select the second number, which is in one (49 times 48) = 2352 the likelihood of getting them both correct.

To select the third number you have a smaller pool of potential numbers available for your choice. To get the third number, which is in one (49 x 48 x 47) = 110544 probable that all three of them correctly.

To select the fourth number one less than in the pool of potential numbers available for your choice. To select the fourth number you have one (49 x 48 x 47 x 46) = 5085024 chance to get all four of them are correct.

To select the fifth number one in the smaller pool of potential numbers available for your choice. To get the fifth number, which is in one (49 x 48 x 47 x 46 x 45) = 228826080 chance to get all five of them are true.

To get the sixth and final issue, which is in (49x48x47x46x45x44) = 10068347520 likelihood of getting all six of them are correct.

So far I have not won a lottery, and I do not know anyone who won the lottery. Practical advice and mathematics that one chance in 10 billion is very close to no chance in 10 billion.
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